Question

8. Three consecutive integers are such that when they
multiplied by 2, 3 and 4 respectively, they add up 74 in increasing order​

Answer 1

Answer:

Let the three consecutive integers be n,n+1,n+2 respectively.

According to the problem,

2n+3(n+1)+4(n+2)=74

or, 9n+11=74

or, 9n=63

or, n=7.

So the numbers are 7,8,9.

Answer 2

Answer:

Let the three consecutive integers be n,n+1,n+2 respectively.

According to the problem,

2n+3(n+1)+4(n+2)=74

or, 9n+11=74

or, 9n=63

or, n=7.

So the numbers are 7,8,9.