Question

8. Three masses of 5 kg, 3 kg and 2 kg are placed on a smooth horizontal surface as shown in figure. When a force of 100 N is applied on it then. Find (i) Acceleration of the system (ii) Tension T1 and T2

Answer 1

Answer:

i)a=10m/s

ii)t1 and t2  

T1=80

T2=60

Explanation:

i)We Know that F=(all masses)a

=>100=10a

=>10a=100

=>a=100/10

a=10m/s

=>a=10m/s

ii)t1 and t2  

T1=F-2a

=>100-2(10)

=100-20

=80

T2=F-2a

=>80-2(10)

=80-20

=60

Please mark me as the brainliest as I have done hard work in solving it

Answer 2

Given:

Mass = m1 = 5kg

Mass = m2 = 3kg

Mass = m3 = 2kg

Force = 100N

To Find:

Tension T1 and T2

Solution:

Equation of force = F = ( m1 + m2 + m3 ) a

= F = (2+3+5)a

100 = 10a

a = 10m/s²  

Now T1

​= F − 2a

T1 = 100 - 2 × 10

T1 = 100 - 20

T1 = 80

Similarly.

T2 = F − 3a

T2 = 100 - 3 × 10

T2 = 100 - 30

T2 = 70

Answer: The values of T1 and T2 are 80 and 70.