Question

8. Three numbers are given in the ratio 2 : 3:5 and the sum of whose squares is 608, the largest
number is
(A) 8
(B) 12
(D) 24
(C) 20​

Answer 1

Answer:

20

Step-by-step explanation:

let the numbers be 2x,3x and 5x.

now,

according to question,

${4x}^{2} + {9x}^{2} + {25x}^{2} = 608$

${38x}^{2} = 608$

so,

${x}^{2} = \frac{608}{38} = 16$

$x = \sqrt{16} = 4$

so , x=4

now , the numbers are

2x=2×4=8

3x=3×4=12

5x=5×4=20

so, the largest number is 20.

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