Question

8. Three pieces of timber ,42m.49m.and 63 m long .have to be divided into planks of the same
length.What is the greatest possible length of each plank​

Answer 1

Step-by-step explanation:

we will find their LCM which is 2×3×7= 42m

Answer 2

Answer:

greatest possible length of each plank =HCF(42,49,63)

The prime factorization of 42,49 and 63 are:

42=2×3×7

49=7 ×7

63=3×3×7

HCF (42,49,63)=7

the greatest possible length of each plank is 7 m.

Step-by-step explanation:

Hope it helps you