Question

8
Three pieces of timber 84 m, 98 m and 126 m long have to be
divide into plants of the same length. What is the greatest
possible length of each plant?
(HOTS​

Answer 1

HCFof 84 98 126

ans. 14 is the correct answer

Answer 2

The greatest possible length of each plant is 14 m.

Explanation:

Given : Three pieces of timber 84 m, 98 m and 126 m long have to be  divide into plants of the same length.

Then, the greatest  possible length of each plant = HCF ( 84 , 98 , 126) m

• HCF= Highest common factor of two or more than two numbers that can divide them completely.

Prime factorization of  84 , 98 , 126 are

$84= 2\times2\times3\times7\\ 98=2\times7\times7\\ 126= 2\times3\times3\times7$

Now ,  HCF ( 84 , 98 , 126)= $2\times7=14$

Hence, the greatest possible length of each plant is 14 m.

# Learn more :

Three pieces of timber 42 m 49 m and 63 m long have to be divided into the planks of the same length. what is the greatest possible length of each plank?

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