Question

8 times a certain number is added to 5 times a second number to give 184 the first number minus the second number is -3 find these numbers

Answer 1

Answer:

The numbers are 13 and 16.

Step-by-step explanation:

Let the numbers be $x$ and $y$. It is given that eight times the first number is added to five times the second number gives 184. That is,

$8x+5y=184$

Also, the second number subtracted from the first number is -3. That is,

$x-y=-3$

We need to solve these equations simultaneously.

Multiply the second equation by 5.

$5x-5y=-15$

Add the above equation with the first equation,

$\implies 8x+5x=184-15\\\\\implies 13x=169\\\\\implies x=\dfrac{169}{13} =13$

So the first number is 13. From the second equation,

$\implies 13-y=-3\\\\\implies y=13+3=16$

So the second number is 16.

Answer 2

QUESTION :

• 8 times a certain number is added to 5 times a second number to give 184 the first number minus the second number is -3 find these numbers

GIVEN :

• 8 times a certain number is added to 5 times

• second number to give 184
• first number minus the second number is -3

TO FIND :

• find these numbers = ?

SOLUTION :

let the number be a and b :-

first we will add 8 with 5 we get :

= 8 +5 = 13

we will minus a - b and write

- 3 :

= a - b = -3

we will multiply - 5 × 3 we get :

• = - 5 × 3 = - 15

then, we will minus 184 with 15

we get :

• = 184 - 15

• = 169

we will divide 169 with 13 we get :

• = 169 ÷ 13

• = 13

we have :

• = 13 - b

• = - 3

we have minus and minus that mean we will add the 13 with 3

we get :

• b = 13 + 3

• = 16

first number = 13

second number = 16