Question

8. Two angles of a quadrilateral are (3x - 4)" and two are (3x + 10)". Find all four angles of a
quadrilateral.(Ans: 83, 83*, 97", 97")
​

Answer 1

GIVEN:-

• Two angles of a quadrilateral are (3x - 4)" and two are (3x + 10)".

TO FIND:-

• Find all the Four angles of a Quadrilateral .

CONCEPT USED:-

• The adjacent angles of the Parallelogram is equal to 180°.

• Opposite sides and angles of Parallelogram are equal.

Now,

----->. (3x-4)° + (3x + 10)° = 180°

------> 3x - 4 + 3x + 10 = 180°

--------> 6x + 6 = 180°

---------> 6x = 174°

---------> x = 174/6

----------> x = 29°.

Putting the value of "x".

--------> (3x + 10)° = 87 + 10 = 97°

(3x + 10)° = 87 + 10 = 97°--------> (3x - 4)° = 87 - 4 = 83°.

Hence, The Four angles of Quadrilateral are 83°, 97° ,83° and 97°.