Question

8. Two arithmetic progressions has the same common difference. If the first term of the first progression is 5 and that of the other is 8, then the difference between their 3rd

Answer 1

Answer:

5

Step-by-step explanation:

Let n_{1}n

1

be the term of the first progression and n_{2}n

2

be the terms of the second progression.

a_{n}=a+(n-1)da

n

=a+(n−1)d , where a is the first term and d is the common difference.

3_{3}=3+(n_{1}-1)3=3+(3-1)3=3+(2)3=3+6=93

3

=3+(n

1

−1)3=3+(3−1)3=3+(2)3=3+6=9

8_{3}=8+(n_{2} -1)3=8+(3-1)3=8+(2)3=8+6=148

3

=8+(n

2

−1)3=8+(3−1)3=8+(2)3=8+6=14

∴ Their difference is 14 - 9 = 5

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