Question

(8)
Two building are facing each other on a road of width 20 m. From top
of one building, which is 15 m high, the angle of elevation with top of
the second building is 60°. Find the height of the second building. (V3 = 1.73)
(Answer:49.60m)​

Answer 1

Answer:

Refer the attachment

Good morning

Have a great day

Answer 2

Answer:

simply dro the diagram

the angle of next building -60

the angle of building in 30

hence

tan30= w/h

tan30=20/15

tan30= 4/3

second building

tan60= w/h

tan60=20/h

√3×20 = h

h =34.6410162