8. Two race cars, Car X and Car Y, are at the starting
point of a 2-km track at the same time. Car X and
Car Y make one lap every 60 s and every 80 s
respectively.
(1) How long, in seconds, will it take for both
cars to be back at the starting point at the
same time?
(ii) How long, in minutes, will it take for the
faster car to be 5 laps ahead of the slower car?
Answers
Answered by
5
Answer:
20 minutes
Step-by-step explanation:
Both will meet again at start point after LCM(60,80) seconds.
That is 240 seconds.
in time slower car completes one lap, faster one covers 1 +20/80 lap, that is 1.25 laps. After 20 laps faster by slower car car will be 5 laps ahead, time =20*60 = 1200s = 20 minutes
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