Math, asked by vrundan75, 8 months ago

8. Two years ago, the age (in years) of Saleem
was three times the age (in years) of his
daughter. Six years hence, the age (in years)
of Saleem will be 4 years more than twice
the age in years) of his daughter. Find the
present age of both of them​

Answers

Answered by RohitGrim
2

Answer:

saleem => 44 , daughter => 16

Step-by-step explanation:

Let 2 years ago , age of daughter be x ,

saleem's age 2 years ago = 3*x.

after two years is current scenario.

saleem's current age = 3*x + 2.

daughter's current age = x+ 2;

now 6 years later ,

saleem's age = 3*x + 2 + 6;

daughter's age = x+2+6;

equation given =>

saleem's age = 2*age of daugher + 4.

3*x+8 = 2*( x+8) + 4

3*x-2*x = 20-8

x = 14.

current age of saleem = 3*x + 2 => 44.

daughter' age => 16.

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