Question

* 8. Two years ago, the age (in years) of Saleem
was three times the age (in years) of his
daughter. Six years hence, the age (in years)
of Saleem will be 4 years more than twice
the age (in years) of his daughter. Find the
present age of both of them​

Answer 1

Answer:

Salim will be four years older than twice her ago. Hence, Salim and his daughter's age are 38 yr and 14 yr, respectively.

Step-by-step explanation:

Let Salim and his daughter's age be x and y yr respectively.

Now, by first condition

Two years ago, Salim was thrice as old as his daughter.

i.e.,  x−2=3(y−2)⇒x−2=3y−6

⇒ x−3y=−4 ...(i)

and by second condition, six years later. Salim will be four year older than twice her ago.

x+6=2(y+6)+4

⇒ x+6=2y+12+4

⇒ x−2y=16−6

⇒ x−2y=10 ...(ii)

On subtracting Eq. (i) from Eq. (ii), we get

x−2y=10x−−3+y=−4+−−−−−−−−−−−− y=14

Put the value of y in Eq. (ii), we get

x−2×14=10

⇒ x=10+28⇒x=38

Hence, Salim and his daughter's age are 38 yr and 14 yr, respectively.