Math, asked by gulabsa5391, 10 months ago

8.Twonumbersareintheratio5:6.If8issubtractedfromeachofthenumbers,the
ratiobecomes4:5.Findthenumbers.

Answers

Answered by wwwacror
3

Answer:

Let the two numbers be x and y.

As per condition 1, i.e., Two numbers are in the ratio 5:6.

The equation becomes,

yx=65

∴6x−5y=0      ..........(1)

As per condition 2, If 8 is subtracted from each of the numbers the ratio is 4:5.

The equation becomes,

y−8x−8=54

∴5x−4y=8     ...........(2)

Equation (1) can be written as x=65y

Substituting x=65y in (2) we get,

y=48

Re substituting y=48 in (1) we get,

x=40

Hence Numbers are 40,48.

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Answered by asahilthakur
2

Answer:

Let the ratio be 5x:6x.

According to Question,

5x-8 : 6x-8 = 4:5

=> 5 (5x-8) = 4 (6x-8)

=> 25x-40 = 24x-32

=> 25x-24x = 40-32

=> x = 8

Hence, first number = 5 × 8 = 40

Second number = 6 × 8 = 48

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