8. Water in a canal, 6m wide and 1.5m deep is flowing with a speed of 10 kmph. How much area will it irrigate in
30 min, if 8 cm of standing water is needed ? (use 1 hector = 10000 m3)
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Answered by
2
Step-by-step explanation:
?
Sol.
Width of the canal = 6 m
Depth of the canal = 1.5 m
Length of water column per hour = 10 km
Length of water column in 30 minutes or 12 hour
=12×10km=5000m
Volume of water flown in 30 minutes
= 1.5 × 6 × 5000 m3=45000m3
Since 8m=8100m
i.e., 0.08 m standing water is desired
Therefore Area irrigated in 30 minutes
=VolumeHeight=450000.08
=562500m2.or56.25hectares
Answered by
1
we know that 1 hectare =10000m^3
so area of field in hectare
=562500/10000
=56.25
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