Math, asked by rushilrushil95, 10 months ago

8. Water in a canal, 6m wide and 1.5m deep is flowing with a speed of 10 kmph. How much area will it irrigate in
30 min, if 8 cm of standing water is needed ? (use 1 hector = 10000 m3)​

Answers

Answered by jagdishgadhvi710
2

Step-by-step explanation:

?

Sol.

Width of the canal = 6 m

Depth of the canal = 1.5 m

Length of water column per hour = 10 km

Length of water column in 30 minutes or 12 hour

=12×10km=5000m

Volume of water flown in 30 minutes

= 1.5 × 6 × 5000 m3=45000m3

Since 8m=8100m

i.e., 0.08 m standing water is desired

Therefore Area irrigated in 30 minutes

=VolumeHeight=450000.08

=562500m2.or56.25hectares

Answered by rk5252
1

we know that 1 hectare =10000m^3

so area of field in hectare

=562500/10000

=56.25

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