Question

8. What sum of money invested at 7.5% p.a. simple interest for 2 years produces twice
as much interest as Rs 9600 in 3 years 6 months at 10% p.a. simple interest?
​

Answer 1

Step-by-step explanation:

First Case:

Principal (P1) = Rs 9600

Rate (R1) = 10%

Period = (T) = 3 years 6 months

= 3

2

1

years = 7 / 2 years

Simple interest = (P × R × T) / 100

= (9600 × 10 × 7) / (100 × 2)

We get,

= Rs 3360

Second case:

Simple interest = Rs 3360 × 2

= Rs 6720

Rate (R) = 7.5% p.a. and

Period (T) = 2 years

Therefore,

Principal = (S.I × 100) / (R × T)

= (6720 × 100) / (7.5 × 2)

= Rs (6720 × 100 × 10) / (75 × 2)

= 6720000 / 150

We get,

= Rs 44800

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Answer 2

Answer:

Rs 44800

Step-by-step explanation:

In first case:

Principal = Rs 9600

Rate = 10%

Period = 3 years 6 months

$= 3 \frac{1}{2} years \\ \\ = \frac{7}{2}years$

Simple interest =

$\frac{p \times r \times t}{100} \\ \\ = \frac{9600 \times 10 \times 7}{100 \times 2} \\ \\ = 3360$

We get Rs 3360.

In second case:

Simple interest = Rs 3360 × 2 = Rs 6720

Rate = 7.5% p.a.

Period = 2 years

So principal

$= \frac{s.i \times 100}{r \times t} \\ \\ = \frac{6700 \times 100 \times 10}{75 \times 2} \\ \\ = \frac{6720000}{150} \\ \\ = 44800$

We get Rs 44800.

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