Question

8. What values of (x, y) satisfy the given equation x3 – 2x2y + 2xy2 - y2 = 0
A. (1,1)
B. (1,2)
C. (2, 1)
D. (3, 1)​

Answer 1

Answer:

A). (1,1)

Step-by-step explanation:

x^3 - 2x^2y + 2xy^2 - y^2 = 0

=> (1)^3 - 2(1)^2 + 2(1)(1)^3 - (1)^2 = 0

=> 1 - 2 + 2 -1 =0

=> 0 = 0

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