Question

8. What would be subtracted from 2x^3
- 3x^2y + 2xy^2 + 3y^2

to get x^3 – 2x^2y + 3xy^2 + 4y^3.
Plz answer it fast with step by step​

Answer 1

Answer:

(2x^3 - 3x^2y + 2xy^2 + 3y^2) - x = (x^3 - 2x^2y + 3xy^2 + 4y^2)

=> 2x^3 - 3x^2y + 2xy^2 + 3y^2

 -    x^3 - 2x^2y + 3xy^2 + 4y^2

    x^3 - 1x^2y   - 1xy^2  - 1y^2

Step-by-step explanation:

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