8. When 50.0 g of MgCO3 react completely with H3PO4, as shown below.15.8 g of CO2 is produced.
Determine the theoretical and percent yield for this reaction?
2 H3PO4 +
3 MgCO3
Mg3(PO4)2 + 3 CO2 + 3 H2O
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Answer:
Explanation:
moles = moles
50/84 = w/44
w=26.19
percentage yield = 60.3
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