Physics, asked by KushalKumar1714, 10 months ago

8.Why is a spherical symmetric surface a convenient choice to prove gauss theorem?

Answers

Answered by Anonymous
2

Answer:

Gauss's law is applicable for any surface/body but in the case where symmetry does not exist, the calculation becomes a bit tedious.

Explanation:

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Answered by sashikantchoubey
2

Answer:

because spherical symmetry reduces the mathematical complexities.. for eg in gauss theorem we evaluate the surface integral , which will be very cumbersome if we have an arbitrary surface..

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