Question

8. Wind with a velocity 100 km h 'blows normally against
one of the walls of a house with an area of 108 m.
Calculate the force exerted on the wall if the air moves
parallel to the wall after striking it and has a density of
1.2 kg m​

Answer 1

Answer:

The value of the force is 10^5N

Explanation:

Let the velocity of the wind is u which blows against the wall of a house having the area s. Now we need o find the force appear on the wall after striking it which has the density d.

The expression to find the force f,

f= s x u^ x d

 = 108×(100×1000/3600)^2×1.2

   =  10^ 5N

Answer 2

Answer:

108×1.2×(100000/36×10^2)^2

=108×1.2×(2777)^2

=100000

=10^5(approx)