8 women and 12 men can together finish a work in 10 days while woman in 8 minutes can finish at 14 days find the time taken by one woman alone to finish the work that also what taken by one man alone ?
Answers
Step-by-step explanation:
Given that: 8 women and 12 men can together finish a work in 10 days while 8 woman can finish in 14 days. find the time taken by one woman alone to finish the work that also what taken by one man alone ?
To find: the time taken by one woman alone to finish the work that also what taken by one man alone ?
Solution: Let the time taken by 1 woman is x days
and time taken by 1 man is y days.
So, one day work of one woman is (1/x)th part of the work.
one day work of 8 women is (8/x)th part of the work.
one day work of a man is (1/y)th part of the work.
one day work of 12 men is (12/y)th part of the work.
So, we can write
because 8 women finish the work in 14 days,so one day work of 8 women
Put value of eq2 in eq1
From eq2, by cross multiplication
One woman alone can finish the work in 8×14 i.e. 112 days.
One man alone finish the work in 420 days.
Hope it helps you.
Given : 8 women and 12 men can together finish a work in 10 days, while 6 women and 8 men can finish it in 14 days.
To Find : the time taken by 1 woman alone to finish the work, and
also that taken by 1 man alone.
Solution :
Let say Man 1 day work = M
& woman 1 day work = W
Total Work 8 women and 12 men can together finish a work in 10 days
=> 8W * 10 + 12M * 10 = 80W + 120M Eq1
Total Work 6 woman and 8 man can together finish a work in 14 days
=> 6W * 14 + 8M * 14 = 84W + 112M Eq2
Equating total work Eq 1 = Eq2
80 W + 120M = 84W + 112M
=> 8M = 4W
=> 2M = 1W
Substitute in Total work Eq 1
Total work = 80(2M) + 120M = 280 M
Hence one man can finish work alone in 280 days
280 M = 140 * 2M = 140W
Hence woman alone can finish in 140 days
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