8 women and 12 men can together
finish a work in 10 days, while 6
women and 8 men can finish it in 14
days. Find the time taken by 1
woman alone to finish the work, and
also that taken by 1 man alone.
Answers
Step-by-step explanation:
Given that:8 women and 12 men can together finish a work in 10 days, while 6 women and 8 men can finish it in 14 days.
To find: Find the time taken by 1 woman alone to finish the work, and also that taken by 1 man alone.
Solution:
In such type of questions,one should always find the work done by men and women in 1 day.
Let
one woman alone can do the work in x days
So, work done by a woman in 1 day = (1/x)th part
one man alone can do the work in y days
So, work done by a man in 1 day = (1/y)th part
Case1: 8 women and 12 men can together finish a work in 10 days
Case2: 6 women and 8 men can together finish a work in 14 days
Now,convert these equations in linear equations ,by substitution
So, equations becomes
after cross multiplication
For elimination method,equate the coefficient of u
Now put the value of v in any of the two equations
Thus
One man alone can finish the work in 280 days and one woman alone can finish the work in 140 days.
Hope it helps you.
Answer:
One man alone can finish the work in 280 days and one woman alone can finish the work in 140 days.