Math, asked by avshesh21, 11 months ago

8 x 2^n+1 = 64, find the value of n?​

Answers

Answered by harsh479175
4

Step-by-step explanation:

8×2^n+1 = 64

16^n+1 =64 on comparison 64/16 =4

n+1 =4

n= 4-1

n=3

hope it helps

Answered by jitekumar4201
0

Answer:

n = 2

Step-by-step explanation:

Given that-

8 × 2^{n+1} = 64

2^{n+1} = \dfrac{64}{8}

2^{n+1} = 8

2^{n+1} = 2^{3}

If bases are same then the power is equals.

So, n + 1 = 3

n = 3 - 1

n = 2

Similar questions