Question

8/(x+3)-3/(2-x)=2 solve the quadratic equation​

Answer 1

Answer:

HOPE IT HELPS....

Answer 2

$\frac{8}{x+3} -\frac{3}{2-x} =2$

$\frac{8(2-x)-3(x+3)}{(x+3)(2-x)}=2$

$\frac{16-8x-3x-9}{-1(x^{2}+x-6 )}=2$

$\frac{-1(-11x+7)}{x^{2}+x-6}=2$

$11x-7=2(x^{2}+x-6)$

$11x-7=2x^{2}+2x-12$

$2x^{2}-9x-5=0$

By using quadratic formula,

$x=\frac{-b\frac{+}{-}\sqrt{b^{2}-4ac}}{2a}$

$x=\frac{-(-9)\frac{+}{-}\sqrt{-9^{2}-4(2)(-5)}}{2(2)}$

$x=\frac{9\frac{+}{-}\sqrt{121}}{4}$

$x=\frac{9\frac{+}{-}11}{4}$

$x=\frac{9+11}{4} or\frac{9-11}{4}$

$x=\frac{15}{4} or\frac{-2}{4}$

∴$x=\frac{15}{4} or\frac{-1}{2}$

hope you find it helpful!!! :)