Math, asked by ms7623342, 19 days ago

8(x-3y)^2 + 4(x-3y) factorise this equation.​

Answers

Answered by pratimakolkata9
1

Answer:

4(x - 3y)(2x - 6y + 1)

Step-by-step explanation:

Let (x - 3y) be a

So our expression becomes 8a² + 4a

= 4a(2a + 1)

= 4(x - 3y)[2(x - 3y) + 1)] (put the value of a return)

= 4(x - 3y)(2x - 6y + 1)

Answered by Anonymous
0

Answer:

[tex]4(2x−3y)2−8x+12y−3

=4(2x−3y)2−4(2x−3y)−3

Let (2x−3y) be a

=4a2−4a−3

=4a2−6a+2a−3

=2a(2a−3)+1(2a−3)

=(2a−3)(2a+1)

Putting the value of a

=[2(2x−3y)−3][2(2x−3y)+1]

=(4x−6y−3)(4x−6y+1)

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