8^x * 4^y = 128 9^(2x-y)=1 find x and y
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8^x*4^y=128 =>
(2^3^x) * (2^2^y) = 2^7 =>
(2^3x)*(2^2y) = 2^7 =>
2^(3x+2y) = 2^7 =>
3x+2y = 7
Finding the possibilities for ‘x’ and ‘y’ in trail and error method, the most common possibility for the above equation is,
x = 1 & y = 2.
To verify this we can substitute the same result in second give equation as 9^x+y=27^xy
9^1+2 = 27^1*2
9^3 = 27^2
729 = 729
So the answer is x = 1 & y = 2.
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