Math, asked by smitpanchal007, 11 months ago

8^x=64/2^x find the value of x​

Answers

Answered by gayatrikumari99sl
3

Answer:

\frac{3}{2} is the required value of x

Step-by-step explanation:

Explanation:

Given that, 8^x = \frac{64 }{2^x}

  • (a^m)^n = a^{mn} is the power rule for exponents. Multiply the exponent by the power to raise a number with an exponent to that power.
  • We employ the same procedures for multiplying exponents with variables as we would for numbers.

Step 1:

From the question we have, 8^x = \frac{64 }{2^x}.

This can be written as, 2^{3x} = \frac{2^6}{2^x}

Subtracting the provided powers is the fundamental rule for dividing exponents with the same base.

2^{3x} = 2^6 . 2^{-x}

2^{3x} = 2^{6 -x}

Now, we compare both the side,

⇒ 3x = 6 - x

⇒4x = 6

⇒ x = \frac{6}{4} = \frac{3}{2}.

Final answer:

Hence, \frac{3}{2} is the required value of x.

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Answered by syed2020ashaels
0

The value of x is 1.5 .

Step-by-step explanation:

  • If a variable's maximum power is always 1, an equation is said to be linear. As a one-degree equation, it also goes by that name. An equation with one variable that has the usual form Ax + B = 0 is a linear equation. A coefficient, B is constant, and x is a variable in this situation. An equation with two variables that has the usual form Ax + By = C is a linear equation. A and B are coefficients, C is a constant, and the variables in this equation are x and y.
  • According to the given information, The equation given here is,

8^{x} = \frac{64}{2^{x} }

Cross multiplying, we get,

8^{x} * 2^{x} = 64

Or, (2^{3} )^{x} * 2^{x} = 64

Or, (2)^{3x} * 2^{x} = 64

Or, 2^{3x + x} = 2^{6}

Or, 2^{4x} = 2^{6}

Comparing the powers on both sides of the equation, we get,

4x = 6

Or, x = \frac{6}{4} \\ = \frac{3}{2} = 1.5

Thus, the value of x is 1.5 .

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