Question

(8- X cube) by(2-x)​

Answer 1

initial steps

$\frac{8 {x}^{3} }{2 - x} \\ = \frac{8 {x}^{3}(2 + x) }{(2 - x)(2 + x)} \\ = \frac{8 {x}^{3}(2 + x) }{ {2}^{2} - {x}^{2} } \\ = \frac{16 {x}^{3} + 8 {x}^{4} }{4 - {x}^{2} }$