8 x square - 22 x minus 21 equal to zero solve it
Answers
it is given that, 8x² - 22x - 21 = 0
first of all, we should check, given polynomial has real roots or not.
find discriminant , D = b² - 4ac
= (-22)² - 4(-21)(8) = 484 + 672 = 1156 = (34)² > 0, discriminant is positive so, given quadratic polynomial has real roots.
now let's start to solve it.
8x² - 22x - 21 = 0
or, 8x² - 28x + 6x - 21 = 0
or, 4x(2x - 7) + 3(2x - 7) = 0
or, (4x + 3)(2x - 7) = 0
or, x = -3/4 and 7/2
hence, zeros of given quadratic are ; -3/4 and 7/2.
Answer:
Solve 8 x square - 22 x minus 21 equal to zero
Solve 8x ² - 22x - 21 = 0
x= 7/2 or -3/4
Step-by-step explanation:
8x ² - 22x - 21
We can use the quadratic formula to solve this equation
The quadratic formula is given as :
For an equation ax² + bx + c
x will be given by:
x = {-b ± √(b² - 4ac)}/2a
In this case: a = 8
b = -22
c = 21
Substitute the values in the eqaution given above to find the value of x
x = {-b ± √(b² - 4ac)}/2a
x = {-(-22) ± √(-22² - (4 × 8 × -21)}/2 × 8
x = {22± √(484 - (-672)} / 16
x = (22 ± √1156) / 16
x = (22 ± 34) / 16
x = (22 + 34) / 16 or (22 - 34) /16
x = 56 / 16 or -12/16
x = 7/2 or - 3/4