Math, asked by kalakrishna9591, 9 months ago

8 x square -22x-21=0​

Answers

Answered by Anonymous
0

Answer:

8x² - 22x - 21

= 8x² - 28x +6x -21

=4x (2x - 7) + 3(2x -7)

= (4x+3) ( 2x-7)

= (4x+3) = 0 or ( 2x-7)

4x = 0-3

or 2x= 0+7x

= -¾, x = 7/2

Answered by aaryankhanduja
0

Answer:

Step-by-step explanation:

8x² - 22x - 21= 0

8x² - 22x - 21= 08x² - 28x +6x -21=0

8x² - 22x - 21= 08x² - 28x +6x -21=04x (2x - 7) + 3(2x -7)= 0

8x² - 22x - 21= 08x² - 28x +6x -21=04x (2x - 7) + 3(2x -7)= 0(4x+3) ( 2x-7) = 0

8x² - 22x - 21= 08x² - 28x +6x -21=04x (2x - 7) + 3(2x -7)= 0(4x+3) ( 2x-7) = 0(4x+3) = 0 or ( 2x-7) = 0

8x² - 22x - 21= 08x² - 28x +6x -21=04x (2x - 7) + 3(2x -7)= 0(4x+3) ( 2x-7) = 0(4x+3) = 0 or ( 2x-7) = 04x = 0-3 or 2x= 0+7

8x² - 22x - 21= 08x² - 28x +6x -21=04x (2x - 7) + 3(2x -7)= 0(4x+3) ( 2x-7) = 0(4x+3) = 0 or ( 2x-7) = 04x = 0-3 or 2x= 0+7x = -¾, x = 7/2

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