8×x×x×x×y×y×z in exponential form
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Step-by-step explanation:
8 can be written as 2³
then
(x)(x)(x)=x³
y×y=y²
z=z¹
then
2³×x³×y²×z¹
(2x)³×y²×z¹
8x³y²z
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