Question

8×x×x×x×y×y×z in exponential form
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Answer 1

Step-by-step explanation:

8 can be written as 2³

then

(x)(x)(x)=x³

y×y=y²

z=z¹

then

2³×x³×y²×z¹

(2x)³×y²×z¹

8x³y²z