[8(x+y)^3-27(x-y)^3]÷[5y-x]=ax^2+bxy+cy^2then the value of a+b+c is
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8(x + y)3 – 27(x – y)3] ÷ (5y – x) = Ax2 + Bxy + Cy2, then, value of (A + B + C) will be:
A. 26
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