Question

8(x + y)^

3 − (x − y)^

3 = (x + 3y)(Ax^

2 + Bxy + Cy^ )

2 . FIND THE VALUE OF A-B-C​

Answer 1

Explanation:

Use Identity: a^3 -b^3 = (a - b) ( a^2 +ab +b^2);

Use Identity: a^3 -b^3 = (a - b) ( a^2 +ab +b^2);2^3(x+y) ^3 - (x-y) ^3= [(2x +2y -x+y)*(4(x+y)^2 +2(x^2-y^2) + (x-y)^2] =

Use Identity: a^3 -b^3 = (a - b) ( a^2 +ab +b^2);2^3(x+y) ^3 - (x-y) ^3= [(2x +2y -x+y)*(4(x+y)^2 +2(x^2-y^2) + (x-y)^2] =(x + 3y)(4x^2 + 4y^2 +8xy + 2x^2 -2y^2 +x^2+y^2–2xy)=

Use Identity: a^3 -b^3 = (a - b) ( a^2 +ab +b^2);2^3(x+y) ^3 - (x-y) ^3= [(2x +2y -x+y)*(4(x+y)^2 +2(x^2-y^2) + (x-y)^2] =(x + 3y)(4x^2 + 4y^2 +8xy + 2x^2 -2y^2 +x^2+y^2–2xy)=(x+3y)(7x^2 +3y^2 +6xy); =>

Use Identity: a^3 -b^3 = (a - b) ( a^2 +ab +b^2);2^3(x+y) ^3 - (x-y) ^3= [(2x +2y -x+y)*(4(x+y)^2 +2(x^2-y^2) + (x-y)^2] =(x + 3y)(4x^2 + 4y^2 +8xy + 2x^2 -2y^2 +x^2+y^2–2xy)=(x+3y)(7x^2 +3y^2 +6xy); =>A=7 ; B = 6; C =3;

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