Question

8(x³y²z²+ x²y³z²+ x²y²z³) = 4x²y²z²
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Answer 1

Step-by-step explanation:

8(x³y²z²+ x²y³z²+ x²y²z³) = 4x²y²z²

2(x³y²z²+x²y³z²+x²y²z³)=x²y²z²

2x²y²z²(x+y+z)=x²y²z²

2(x+y+z)=x²y²z²/x²y²z²

2x+2y+2z-1=0