Math, asked by mahendradabhi115, 4 months ago

8(x³y²z²+x²y³z²+x²y²z³)÷4x²y²z²

Answers

Answered by Anonymous

2

Answer:

8(x³y²z²+x²y³z²+x²y²z³)/4x²y²z²=8x²y²z²(x+y+z)/4x²y²z²=2(x+y+z)

Answered by Anonymous

0

8(x³y²z²+x²y³z²+x²y²z³) ÷ 4x²y²z²

2(x³y²z²+x²y³z²+x²y²z³) ÷ x²y²z²

2x³y²z²/x²y²z² + 2x²y³z²/x²y²z² + 2x²y²z³/x²y²z²

2x + 2y + 2z

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