Question

8.
y is older than x by 7 years 15 years back x's age was 3/4 of y's age. Their present ages are:
a) (x=36, y=43)
b) (x=50, y 43)
c) (x=43, y=50)
d) (x=40, y 47)​

Answer 1

Answer:

option (a) is correct .

Step-by-step explanation:

Let their present ages be X and Y

Now, Y is 7 years older than X

Y = X+7

15 years ago their ages were

X-15 and Y-15

Y-15 = X+7–15= X-8

15 years back X age was 3/4 of Y's age

X-15 = 3/4(Y-15)

X-15 = 3/4(X-8)

4X-60=3X-24

X= 36

Y= X+7= 43

Thus their present ages are 36yrs and 43yrs

I hope this helps:)

✌✌

if it helped then plz like and mark brainliest !!