8 year ago, Neelam was four times as old as her daughter.8 year hence, Neelam will be two times as old as a daughter find their present ages
Answers
- Let the present age of Neelam be x.
- Let the present age of her daughter be y.
By data,
8 years ago, Neelam was four times as old as her daughter.
- The age of Neelam before 8 years is x-8
- The age of the daughter before 8 years is y-8
Let the above equation be equation 1.
Again by data,
8 year hence, Neelam will be two times as old as a daughter.
- Neelam's age after 8 years be x+8
- He age of daughter after 8 years is y+8
Let the above equation be equation 2.
Adding equations 1 and 2.
The present age of Neelam's daughter is 16.
Substitute y = 16 in equation 2
The present age of Neelam is 40.
- 8 years ago , Neelam was 4times as old as her daughter.
- 8years hence , Neelam will be two times as old as her faughter.
- Present age of Neelam and daughter.
Let the present age of Neelam be 'x' and daughter be 'y'.
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According to question ,
- 8years ago , Neelam was 4times as old as her daughter.
8years ago ,
- Neelam age = (x-8)yrs
- Daughter age = (y-8)yrs
So,
➥ x - 8 = 4(y-8)
➥ x - 8 = 4y - 32
➥ x - 4y = -32+8
➣ x - 4y = -24 ______(1)
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Also ,
- 8years hence , Neelam will be 2times as old as her daughter.
8yrs hence ,
- Neelam age = (x+8)yrs
- Daughter age = (y+8)yrs
So,
➥ x+8 = 2(y+8)
➥ x+8 = 2y+16
➥ x - 2y = 16 - 8
➥ x - 2y = 8
Multiplying both sides by 2, we get..
➥ 2(x - 2y) = 8×2
➣ 2x - 4y = 16 ______(2)
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Substracting equation (2) by equation (1),
➾ (x - 4y) - (2x - 4y) = -24-16
➾ x - 4y - 2x + 4y = -40
➾ -x = -40
∴ x = 40years
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➙ Putting x = 40 in equation (1) , we get...
➛ x - 4y = - 24
➛ 40 - 4y = - 24
➛ - 4y = - 24 - 40
➛ - 4y = - 64
∴ y = 16years
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