Math, asked by sabnamSultana690, 1 year ago

8 years ago the age of Raju was 4 times the age of his brother Rana. after 12 years Rana's age will be 2/3 of Raju's age. the present age of Raju and Rana are- (a)18 years, 12 years (b)16 years, 12 years (c)24 years, 12 years (d)20 years, 14 years
please step by step explain kar do koi

Answers

Answered by sneharauniyar180
1

y ka ans 10 aaya mera

aapka toh 12 ka option hai

Attachments:
Answered by mythu67
4

Answer:

(c)

Step-by-step explanation:

*8 years ago*

Raju = 4 x Rana

*12 years later*

Rana = 2/3 x Raju

Let Rana's current age be 'x'.

Then, Raju's current age - 8 = 4 x (Rana's current age - 8)  ···[current age - 8 = age 8 years age]

⇒ Raju's current age - 8 = 4(x - 8)

⇒ Raju's current age = 4x - 32 + 8

⇒ Raju's current age = 4x - 24

⇒ Raju's current age = 4(x - 6)

Also, Rana's current age + 12 = 2/3 x Raju's current age + 12  

⇒ x + 12 = 2/3(4x - 24 + 12)

⇒ x + 12 = 8x/3 - 16 + 8

⇒ x + 12 = 8x/3 - 8

⇒ 8x/3 - x = 12 + 8

⇒ 8x/3 - 3x/3 = 20

⇒ 5x/3 = 20

⇒ x = 20 x 3/5

⇒ x = 12 years

∴ Rana's current age is 12 years.

⇒ Raju's current age is 4(x-6) = 24 years.

So, the answer is option (c) 24 years, 12 years

Hope this helped!

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