Question

8 years ago the age of the father was 4 times the age of the son.after 12 years ago of the father will be twice the age of the son. find their present ages​

Answer 1

Answer:

Step-by-step explanation:

The son is 7 years old.

The problem can be represented by a system of equations. Where 1 equation represents the relationship between their current ages and how old they were 4 years ago and one represents the current relationship of their ages.

F = Fathers Current Age

S = Sons Current Age

So 4 years ago

F-4 = 8 (S-4)

F = 4S

The first equation is the more tricky one and people will usually leave out the -4 for the son.

The second equation is already solved for the F variable so take that expression that is equivalent to F (4S) and plug it into the first equation. Now you will have a one variable equation which can be solved for the sons current age.

4S-4=8(S-4)

4S-4=8S-32

Add 32 and subtract 4s from both sides.

28 = 4S

S=7

The sons current age is 7, his father is currently 28, and four years ago the son would have been 3 and his father 24.

Answer 2

sorry I didn't know the answer...