Math, asked by taufiq97, 9 months ago

8 years ago, the ratio of A's
ago to B's age was 4 : 5. At
present the ratio of B's age to
C's age is 4 : 5. At present,
the difference between A's
age and C's age is 20 years,
then what is the sum of the
ages of A, B and C? → 148
years​

Answers

Answered by muskansaroj23
0

yes......absolutely correct

Answered by tyrbylent
1

Answer:

Step-by-step explanation:

Current age of persons

A (years) , B = 4x (years) , C = 5x (years) and (5x - A) = 20 ===> A = 5x - 20

(5x - 20), 4x, 5x

8 years ago age of person A and person B were:  

(A - 8) years and (B - 8) years , and

\frac{A-8}{B-8} = \frac{4}{5} ===> 5A - 40 = 4B - 32

5A - 4B = 8

5(5x - 20) - 4(4x) = 8

25x - 16x = 108

9x = 108

x = 12

Person A is 40 years old

Person B is 48 years old

Person C is 60 years old

A + B + C = 148 years

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