8 years before Vishal age is 4 times of his sons age name Shekhar after 8 years Vishal age is double of his son's age find there ages
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Solution==>
Let age of Vishal=x
and, let age of his son Shekhar=y
As per question==>
Case 1<=>Before 8 years
Age of Vishal=x-8
Age of his son=y-8
x-8=4(y-8) (given, as A.T.Q)
x-8=4y-32
x-4y=-32+8
x-4y=-24.........(1)
Case 2<=>After 8 years
Age of Vishal=x+8
Age of his son=y+8
x+8=2(y+8) (given, as A.T.Q)
x+8=2y+16
x-2y=16-8
x-2y=8...........(2)
Solving (1) and (2) by elimination method
x-4y=-24
x-2y=8
- + -
-----------
-2y=-30
------------
-2y=-30
2y=30
y=30/2
y=15
now, put y=15 in (1)
x-4y=-24
x-4(15)=-24
x-60=-24
x=-24+60
x=36
Therefore,
Age of Vishal=x=36 years
and, Age of his son=y=15 years
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