Question

80–[3×{12– (8÷4)×2}+3]

Answer 1

80-[3*(12-(8/4)*2)+3]
= 80-[3*(12-4)+3]
= 80-(27)
= 53

Answer 2

In this problem, we are assuming we have to solve the given expression.

Q. Solve$80-[3\times[12- (8\div4)\times2]+3]$

Given: $80-[3\times[12- (8\div4)\times2]+3]$

We have to solve the above expression.

By using the Bodmas rule, we are solving the above expression.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$80-[3\times[12- (8\div4)\times2]+3]$

Solving the above expression further we get,

$= 80-[3\times{12-(8/4)\times2}+3]\\= 80-[3\times{12-(2)\times2}+3]\\= 80-[3\times{12-2\times2}+3]= 80-[3\times{12-4}+3]= 80-[3\times{8}+3]\\\\= 80-[3\times8+3]\\= 80-[24+3]\\= 80-[27]\\= 80-27\\= 53$

Hence, we get the solution is$53$.