Question

80% carbon is present in an alkane by weight. The possible conclusions are
a) The empirical formula of the compound is CH,
b) The minimum number of carbons in the molecule is 2
c) The compound has gram atoms of C & H in 4:1 ratio
d) This composition suits to all alkanes​

Answer 1

Answer:

C9H20

Nonane/Formula

The nine carbon atoms are connected in one long chain with no branches. Hydrogens are attached such that each carbon makes four bonds to other atoms. Nonane's molecular formula is C9H20 and its structure can be drawn in many ways that are all equivalent in the field of chemistry.

Answer 2

Answer:

The possible conclusion is the minimum number of carbons in the molecule is 2. The empirical formula of the compound is CH₃.

Therefore, option (b) is correct.

Explanation:

Given, the weight of carbon in alkane  = 80%

The weight of hydrogen = 20

Element    % weight       Atomic mass    weight/at. mass      Simple ratio

C                80                     12                    80/12 = 6.67                1

H               20                      1                      20/1 = 20                     3

Therefore, the empirical formula of the compound is CH₃.

The molecular formula of the alkane can be (CH₃)₂ or C₂H₆.

Therefore, the minimum number of carbons in the one molecule of the alkane is 2.

The number of gram atoms:-  $n_C =\frac{24}{12} = 2\; \; and \;\; n_H =\frac{6}{1} =6$.

The ratio of gram atoms of C & H in alkane is 1 : 3.

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