Math, asked by kitkrut4534, 11 months ago

80 chocolates are to be packed such that each packet has an equal number of chocolates.what are the different combination of numbers in which they can be packed?

Answers

Answered by doronq1
2

Answer:

the answer is: 10

Step-by-step explanation:

Think of all the dividers of the number 80,

80 (1 pack), 40 (2 packs), 20 (4 packs), 16 (5 packs), 10 (8 packs), 8 (10 packs), 5 (16 packs), 4(20 packs), 2 (40 packs) and finally 1(80 packs)

Answered by sk940178
6

There can be ten combination of numbers in which 80 chocolates can be packed.

Step-by-step explanation:

There are 80 chocolates to be packed such that each packet has an equal number of chocolates.

Therefore,  

(i) There can be 80 packets with 1 chocolate in each packet.

(ii) There can be 40 packets with 2 chocolates in each packet.

(iii) There can be 20 packets with 4 chocolates in each packet.

(iv) There can be 16 packets with 5 chocolates in each packet.

(v) There can be 10 packets with 8 chocolates in each packet.

(vi) There can be 8 packets with 10 chocolates in each packet.

(vii) There can be 5 packets with 16 chocolates in each packet.

(viii) There can be 4 packets with 20 chocolates in each packet.

(ix) There can be 2 packets with 40 chocolates in each packet.

(x) There can be 1 packet with 80 chocolates in it.

Therefore, there can be ten combinations of numbers in which 80 chocolates can be packed. (Answer)

Similar questions