Question

80 coins are placed in a straight line on the ground. The distance between any two consecutive

coins is 15 metres. How far must person travels to bring them one by one to a basket placed 15
meters behind first coin.




plzz answer this question​

Answer 1

Answer:

total distance traveled = 11880m =

11.880km

Step-by-step explanation:

to get first coin he has to travel

= 15+15=30 m

to get second = 30+30 =60m

to get 3rd = 45+45=90m

there are 80 coins n=80

series 30, 60, 90,.............

a=30, d= 60-30=30. n=80

sum =

$= \frac{n}{2} (2a + (n - 1)d)$

$= \frac{80}{2} (2 \times 30 + (80 - 1)30)$

$= 40(60 + 237)$

$= 40 \times 297$

$= 11880m$

total distance traveled = 11880m = 11.880km

Answer 2

Answer:

total distance traveled = 11880m = 11.880km

Step-by-step explanation:

to get first coin he has to travel = 15+15=30 m

to get second = 30+30 =60m  

to get 3rd = 45+45=90m

there are 80 coins n=80

series 30, 60, 90,.............

a=30, d= 60-30=30. n=80

sum =total distance traveled = 11880m = 11.880km