Question

80 gram of H2 is reacted with 80 gram of O2 to form water find out the mass of water obtained which substance is the limiting reagent

with steps pls

Answer 1

2H2 + O2→2 H2O

4gm H2 requires 32gm O2 to form 36gm H2O

80gm H2 requires 640gm O2,but the provided O2 act is less than required hence, O2 act as limiting reagent.

32gm O2 forms 36gm H2O

80gm O2 forms 90gm H2O.