80 gram of H2 is reacted with 80 gram of O2 to form water find out the mass of water obtained which substance is the limiting reagent
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90gram of water obtained bcz 80÷32 mole of O2 formed 2 mole of H20 so 5 mole of H20 formed
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satwik72:
90 anwer bcz 80÷32 tha 16 nahi
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hope this image helps you
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