80 gram of hydrogen gas is reacted with 80 gram of oxygen gas to form water.Find the mass of water obtained.
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according to reaction of water formation
80 gram hydrogen and 40 g oxygen will combine and will form 80 gram of water ... this is bcz of stoichiometry calculation
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80g of hydrogen = 80÷2 moles= 40moles
80g if oxygen = 80÷32 moles
since, moles of O2 is lesser than H2, O2 is limiting reagent
=) 16 g O2 gives= 18g water
=) 80g O2 gives= 18×80÷16
= 90 g
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