Question

80 grams CO2 is filled in a spherical ball at STP. Find the radius of the ball.​

Answer 1

Given mass of CO2 = 80g

We know, mass of

C = 12 g , O = 16 g

So, Molar mass of CO2

==> 12 + 16×2

==> 12 + 32

==> 44 g

number of moles = mass given / molar mass

==> number of moles = 80/44

==> number of moles = 1.8 moles

Also,

We know

==> number of moles = Volume given ( in dm³) / ( volume at S.T.P ( 22.4 dm³ ) )

==> volume / 22.4 = 1.8

==> volume = 22.4 × 1.8

==> volume = 40.32 dm³

Also, Given that the gas is filled in a spherical ball. So

Volume of Spherical ball = 4/3 πr³

==> 4/3 πr³ = 40.32

==> πr³ = 30.24

==> r³ = 9.63 { take, π = 3.14 }

==> r ≈ 2.12 dm

Hence, Radius of spherical ball is 2.12 dm

Answer 2

Answer:

r=2.13406

Explanation:

PLEASE DONT FORGET TO LIKE THE ANSWER AND RATE THE ANSWER