80 kg and a kinetic energy of 2560 J. What is the speed
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We know that:÷
K.E = 1/2 mv^2
substituting the given values
2560=1/2 80 v^2
2560=40v^2
2560÷40=v^2
1024=v^2
v=square root of 1024
v=32
I guess this is correct
K.E = 1/2 mv^2
substituting the given values
2560=1/2 80 v^2
2560=40v^2
2560÷40=v^2
1024=v^2
v=square root of 1024
v=32
I guess this is correct
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